{"id":11,"date":"2019-02-05T14:43:23","date_gmt":"2019-02-05T14:43:23","guid":{"rendered":"https:\/\/www.kindsonthegenius.com\/coding\/?p=11"},"modified":"2019-02-05T17:19:51","modified_gmt":"2019-02-05T17:19:51","slug":"question-2-check-if-subarray-with-zero-sum-exists","status":"publish","type":"post","link":"https:\/\/www.kindsonthegenius.com\/coding\/question-2-check-if-subarray-with-zero-sum-exists\/","title":{"rendered":"Question 2: Check if Subarray with Zero Sum Exists"},"content":{"rendered":"

Question 2<\/strong><\/p>\n

You are given an integer array. You need to check if the array contains sub-array with zero sum.<\/p>\n

For example:<\/p>\n

Input<\/strong>: A = {4, -1, -3, 1}<\/p>\n

Output<\/strong>: Subarray with zero sum exists<\/p>\n

{4, -1, -3}<\/p>\n

 <\/p>\n

Solution 1: Inefficient Solution – Quadratic Time – O(n2<\/sup>)<\/strong><\/h4>\n

In this solution we take running sum of all each element with every other element, and each time we check if the sum is equal to zero. If yes then we return true.<\/p>\n

The Java code is given below:<\/p>\n

\/*<\/span>\r\n * Written by: Kindson The Genius<\/span>\r\n *\/<\/span>\r\npublic<\/span> class<\/span> ZeroSumSubarray1<\/span> {<\/span>\r\n\t\r\n\tpublic<\/span> static<\/span> boolean<\/span> zeroSumSubarray<\/span>(<\/span>int<\/span> A[])<\/span> {<\/span>\r\n\t\tint<\/span> sum;<\/span>\r\n\t\t\r\n\t\tfor<\/span>(<\/span>int<\/span> i =<\/span> 0<\/span>;<\/span> i <<\/span> A.<\/span>length<\/span>;<\/span> i++)<\/span> {<\/span>\r\n\t\t\tsum =<\/span> 0<\/span>;<\/span>\r\n\t\t\t\r\n\t\t\tfor<\/span>(<\/span>int<\/span> j =<\/span> i;<\/span> j <<\/span> A.<\/span>length<\/span>;<\/span> j++)<\/span> {<\/span>\r\n\t\t\t\tsum =<\/span> sum +<\/span> A[<\/span>j];<\/span>\r\n\t\t\t\tif<\/span>(<\/span>sum ==<\/span> 0<\/span>)<\/span> {<\/span>\r\n\t\t\t\t\tSystem.<\/span>out<\/span>.<\/span>println<\/span>(<\/span>\"Subarray exists\"<\/span>);<\/span>\r\n\t\t\t\t\treturn<\/span> true<\/span>;<\/span>\r\n\t\t\t\t}<\/span>\t\t\t\t\r\n\t\t\t}<\/span>\/\/end of for loop\t\t\t<\/span>\r\n\t\t}<\/span>\/\/end of for loop<\/span>\r\n\t\t\r\n\t\tSystem.<\/span>out<\/span>.<\/span>println<\/span>(<\/span>\"Subarray does not exist\"<\/span>);<\/span>\r\n\t\treturn<\/span> false<\/span>;<\/span>\r\n\t}<\/span>\/\/end of zeroSumSubarray<\/span>\r\n\r\n\t\r\n\tpublic<\/span> static<\/span> void<\/span> main<\/span>(<\/span>String[]<\/span> args)<\/span> {<\/span>\r\n\t\tint<\/span> ar[]<\/span> =<\/span> {<\/span>4<\/span>,<\/span> -<\/span>1<\/span>,<\/span> -<\/span>3<\/span>,<\/span> 1<\/span>};<\/span>\r\n\t\tzeroSumSubarray(<\/span>ar);<\/span>\r\n\t}<\/span>\r\n}<\/span>\r\n<\/pre>\n
 <\/p>\n
<\/h4>\n
Solution 2: Using a Hash Table – Linear Time O(n)<\/strong><\/h4>\n
In this solution, start from the first element and take running sum. Then for each element, we store the sum so far in a hash table. Before we store an element, we check the hash table\u00a0 to see if the sum already exists (ie if it has been seen before). If yes, then we know hat there is\u00a0 a sub-array with zero sum that ends at the current index.<\/p>\n
The Java program is given below:<\/p>\n
\/*<\/span>\r\n * Written by Kindson the Genius<\/span>\r\n * Check is Subarry with zero sum exists<\/span>\r\n *\/<\/span>\r\n\r\nimport<\/span> java.util.HashSet<\/span>;<\/span>\r\nimport<\/span> java.util.Set<\/span>;<\/span>\r\n\r\npublic<\/span> class<\/span> ZeroSumSubarray2<\/span> {<\/span>\r\n\t\r\n\tpublic<\/span> static<\/span> Boolean ZeroSumSubarray<\/span>(<\/span>int<\/span> A[])<\/span> {<\/span>\r\n\t\tSet<<\/span>Integer><\/span> set =<\/span> new<\/span> HashSet<<\/span>Integer>();<\/span>\r\n\t\t\r\n\t\tint<\/span> sum =<\/span> 0<\/span>;<\/span>\r\n\t\t\r\n\t\tset.<\/span>add<\/span>(<\/span>sum);<\/span>\r\n\t\t\r\n\t\tfor<\/span>(<\/span>int<\/span> i =<\/span> 0<\/span>;<\/span> i<<\/span>A.<\/span>length<\/span>;<\/span> i++)<\/span> {<\/span>\r\n\t\t\tsum =<\/span> sum +<\/span> A[<\/span>i];<\/span>\r\n\t\t\t\r\n\t\t\tif<\/span>(<\/span>set.<\/span>contains<\/span>(<\/span>sum))<\/span> {<\/span>\r\n\t\t\t\treturn<\/span> true<\/span>;<\/span>\r\n\t\t\t}<\/span>\r\n\t\t\t\r\n\t\t\tset.<\/span>add<\/span>(<\/span>sum);<\/span>\r\n\t\t\t\r\n\t\t}<\/span>\/\/end of for loop<\/span>\r\n\t\t\r\n\t\treturn<\/span> false<\/span>;<\/span>\r\n\t}<\/span>\/\/end of function<\/span>\r\n\t\r\n\tpublic<\/span> static<\/span> void<\/span> main<\/span>(<\/span>String[]<\/span> args)<\/span> {<\/span>\r\n\r\n\t\tint<\/span> ar[]<\/span>  =<\/span> {<\/span>1<\/span>,<\/span> -<\/span>4<\/span>,<\/span> 3<\/span>,<\/span> 4<\/span>};<\/span>\r\n\t\t\r\n\t\tSystem.<\/span>out<\/span>.<\/span>println<\/span>(<\/span>ZeroSumSubarray(<\/span>ar));<\/span>\r\n\t}<\/span>\r\n}<\/span>\r\n<\/pre>\n","protected":false},"excerpt":{"rendered":"
Question 2 You are given an integer array. You need to check if the array contains sub-array with zero sum. For example: Input: A = … <\/p>\n","protected":false},"author":395,"featured_media":12,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[8,2,3],"tags":[],"class_list":["post-11","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-array","category-coding-challenge","category-java"],"yoast_head":"\nQuestion 2: Check if Subarray with Zero Sum Exists - Coding Challenge<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.kindsonthegenius.com\/coding\/question-2-check-if-subarray-with-zero-sum-exists\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Question 2: Check if Subarray with Zero Sum Exists - Coding Challenge\" \/>\n<meta property=\"og:description\" content=\"Question 2 You are given an integer array. 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